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3 years ago

Mrs. Monroe is painting her room and she uses 5 gallons of paint. How many pints of paint did she use?

Mathematics

2 answers:

myrzilka [38]3 years ago

5 0

Answer:

She used 40 pints.

Step-by-step explanation:

I used an chart. The chart said that 8 pints are in a gallon so, you multiply 8 pints by 5 gallons and you get 40 pints.

<h2>I hope this is your right answer and please mark as brainllest You welcome. </h2><h2>have a great day!!❤️</h2>

Veseljchak [2.6K]3 years ago

3 0

Answer:

40 pints of paints

Step-by-step explanation:

there are 8 pints in a gallon

8 x 5 = 40

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We have been given that a person places $6340 in an investment account earning an annual rate of 8.4%, compounded continuously. We are asked to find amount of money in the account after 2 years.

We will use continuous compounding formula to solve our given problem as:

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P = Principal initially invested,

e = base of a natural logarithm,

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An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

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$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

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Scorpion4ik [409]

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Musya8 [376]

Answer:

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Step-by-step explanation:

Elizabeth is selling jam at a farmers market.

She earns $5 for each jar of Jan that she sells

Her goal is to earn $450 during the weekend.

Elizabeth has already made $95 from the sale of her jams and $24 from leading a demonstration

Therefore the total amount that has been made is

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Since her target is $450 and she has already made $119 then the amount remaining to complete the target can be calculated as follows

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