Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
Answer:
A D F
Step-by-step explanation:
i think
pls mark brainliest
Answer: 2.5 hours is the answer
Step-by-step explanation:
It took Travis 2.5 hours to complete 3/4 of his trip. To find the average speed, we need to find his speed during 3/4 of the trip and then the 52.5 miles.
So you know that 52.5 is 1/4 of his total trip. That means if we multiply that by 3, that's how many miles he traveled in 2.5hrs. (157.5)
To calculate speed, divide distance by time.
For 3/4 of his trip (157.5), it took him 2.5 hours.
157.5/2.5 = 63mph
For the remaining 52.5 miles, it took him an hour.
52.5/1 = 52.5mph
Now average those two speeds to get the average speed for the whole trip.
(63+52.5)/2= 57.6mph
