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You manage small LAN for a branch office. The branch office has three file servers and few client workstations. You want to use Ethernet device and offer guaranteed bandwidth to each server. You design the network by <u>connecting all network devices to a switch. Connect each server to its own switch port.</u>
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Explanation:
- A local-area network (LAN) is a computer network that spans a relatively small area.
- Most often, a LAN is confined to a single room, building or group of buildings, however, one LAN can be connected to other LANs over any distance via telephone lines and radio waves.
- The LAN is the networking infrastructure that provides access to network communication services and resources for end users and devices spread over a single floor or building.
- Designing a LAN for the campus use case is not a one-design-fits-all proposition.
- If there is a single 48-port switch, 47 devices can be supported, with only one port used to connect the switch to the rest of the network, and only one power outlet needed to accommodate the single switch
Answer:
A top-level domain or the TLD is the domain at the highest level in the hierarchy of the DNS. And that means in the Internet DNS. Also, the top-level domain is installed in the namespace toot zone. And the top-level domain is the .com, in general, to be named as the best one. The next two are the .net and .org. But since it is required to optimize the website for the mobile devices, we should select here .com.
Explanation:
Please check the answer section.
MOHR-COULOMB FAILURE CRITERIA:
In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.
If you can not understand the below symbols see the attachment below
f f ()
Where: f = Shear Stress on Failure Plane
´= Normal Stress on Failure Plane
See the graph in the attachment
For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula: shear stress = f c tan
Where,
• f is Shear Stress on Failure Plane
• c is Cohesion
• is Normal Total Stress on Failure Plane
• is Friction Angle
