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3 years ago

1. Find the equivalent fraction of 3/4

Mathematics

2 answers:

rewona [7]3 years ago

8 0

Step-by-step explanation:

SOLUTION 1 :-

→ 3/4

→ 3 × 2/ 4×2

→ 6/8

SOLUTION 2 :-

→ 2 - 3/5

→ 10 - 3/5

→ 7/5

SOLUTION 3 :-

→ 4 + 7/8

→ 32 + 7/8

→ 39/8

SOLUTION 4:-

→ 3/5 + 2/7

→ 21 + 10 / 35

→ 31/35

SOLUTION 5 :-

→ 9/11 - 4/15

→ 135 - 44/165

→ 91/165

SOLUTION 6:-

→ 7/10 + 2/5 + 3/2

→ 7 + 4 + 15/10

→ 26/10

→ 13/5

aleksklad [387]3 years ago

3 0

Answer:

6/8

Step-by-step explanation:

I have no reason to explain its simple just reduce 6/8

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A town has a population of 8000 and grows at 3% every year. To the nearest tenth of a year, how long will it be until the popula

Alexxx [7]

Answer:

It will take approximately 34 years

Step-by-step explanation:

If a town population is 8000 and grows 3% annually.

How long will it take to reach 16300

growth is 16300 - 8000 = 8300

using simple interest formula

SI = (P × r × t)/100

8300 = (8000 × 3 × t)100

8300= (80 × 3)t

8300 = 240t

t = 8300/240

t ≈ 34 years to the nearest tenth

8 0

3 years ago

3/5+(-7/5)= can someone help me with this please

Tresset [83]

Answer:

$-\frac{4}{5}$

Step-by-step explanation:

Because both of the fractions have a common denominator they can be subracted without any other work.

4 0

3 years ago

Help me solve this please

damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative

$0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)$

$d = b^2 - 4ac = (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0$

Dividing by 4,

$k^2 - 4 k + 3 < 0 \quad\checkmark$

We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.

$(k-3)(k-1)$

That's true for

$1 < k < 3$

2) We look for the meet of the line and the parabola:

$2x + k + 2 = 2x^2 + (k+2)x + 8$

$0 = 2x^2 + kx + (6-k)$

For two intersections we need a positive discriminant:

$k^2 - 4(6-k)(2) > 0$

$k^2 + 8k - 48 > 0$

$(k+12)(k-4) > 0$

That's means two negative or two positive, so

$k < 12$ or $k > 4$

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4 years ago

Can you guys help me find the product rule of the question in the blue box?

ziro4ka [17]

Answer:

${a}^{m} \times {a}^{n} = {a}^{m + n}$

Step-by-step explanation:

Its a law of indices

4 0

3 years ago

The sum of a number and 6

LenKa [72]

Answer:

Step-by-step explanation:

2x=6 hence the number is 3

6 0

3 years ago