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Sphinxa [80]
1 year ago
7

Diagram 1 shows absolute function of f(x)= 3x-1a)State the domain for that functionb)State the value of a

Mathematics
1 answer:
omeli [17]1 year ago
3 0

The function given is,

f(x)=3x-1

a) Domain

This is the set of all points over which a function is defined.

Therefore, the domain of the function is

-2\leq x\leq1

b) Solving for the value of a

To solve for the value of a, the value of y = 0 at x = a

Therefore,

\begin{gathered} f(x)=3x-1 \\ \text{where,} \\ f(x)=y=0 \\ x=a \end{gathered}

Solving for a

\begin{gathered} 0=3(a)-1 \\ 0=3a-1 \\  \end{gathered}

Collect like terms

\begin{gathered} 3a=0+1 \\ 3a=1 \end{gathered}

Divide both sides by 3

\begin{gathered} \frac{3a}{3}=\frac{1}{3} \\ a=\frac{1}{3} \end{gathered}

Hence,

a=\frac{1}{3}

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Solve:<br><br>1/5c =15<br><br>c=__<br>solve what c equals
grin007 [14]

Answer:

75

Step-by-step explanation:

a fifth of c is 15

75÷5=15

4 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
What is the value of x in the figure Pls help​
Murljashka [212]

Answer: x=18

im assuming that this is a right angle

so if it is then that means the total of the angle should be 90 degrees. so 2x+3x should be equal to 90. Just combine like terms to get that 5x=90 and then isolate the variable (divide by 5 on both sides) so x ends up equaling 18.

so x=18

7 0
3 years ago
How many variable terms are in the expression 3x3y + 5xz − 4y + x − z + 9?
Dimas [21]

Answer:

3

Step-by-step explanation:

there are only x y and z used in the expression no matter how many times they multiply.

8 0
2 years ago
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