Answer:
the probability of no defects in 10 feet of steel = 0.1353
Step-by-step explanation:
GIven that:
A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.
Let consider β to be the average value for defecting
So;
β = 2
Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.
Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2
i.e

the probability mass function can be represented as follows:

where;
y = 0,1,2,3 ...
Hence, the probability of no defects in 10 feet of steel
y = 0


P(y =0) = 0.1353
Answer:
Point D
Step-by-step explanation:
Hope this helps :)
0.003 is 1/10 of 0.03.
Just multiply the 0.003 by 10 and you'll get the answer.
Answer:
88unit^2
Step-by-step explanation:Area=
1/2(17+27)*4
Area=88unit^2