ANSWER: ⇒ ¹/₃
Solve the equation:
6a - 4 = -2
Rearrange variables to the left side of the equation:
6a = -2 + 4
Calculate the sum or difference:
6a = 2
Divide both sides of the equation by the coefficient of variable:
a = ²/₆
Cross out the common factor:
a = ¹/₃
Answer:
54 ~ see below for explanation
Step-by-step explanation:
you're going to replace n with the 6 since n= 6
so (8+3)6
then you're going to add 8+3 in the parenthesis because of PEMDAS
(9)6
you're going to multiply 6 by 9 since 9 is in parenthesis (a number in parenthesis means multiply)
then you get 54 so the answer would be 54.
Answer: 62°
Step-by-step explanation:
Total angle in a triangle = 180°
40° + 78° + < N = 180°
118° + <N =180
<N = 180 -118
<N=62°
Hi there,
X x (-2) x 2 = 4 x (-2)
- x = - 2
Hence, X = 2
Hope this helps :)
![\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\ -------------------------------\\\\ sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2} \\\\\\ sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right) \\\\\\ \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}](https://tex.z-dn.net/?f=%5Cbf%20sin%5E2%282%5Ctheta%29-7sin%282%5Ctheta%29-1%3D0%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Asin%282%5Ctheta%29%3D%5Ccfrac%7B7%5Cpm%5Csqrt%7B49-4%281%29%28-1%29%7D%7D%7B2%281%29%7D%5Cimplies%20sin%282%5Ctheta%29%3D%5Ccfrac%7B7%5Cpm%5Csqrt%7B49%2B4%7D%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%282%5Ctheta%29%3D%5Ccfrac%7B7%5Cpm%5Csqrt%7B53%7D%7D%7B2%7D%5Cimplies%202%5Ctheta%3Dsin%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B7%5Cpm%5Csqrt%7B53%7D%7D%7B2%7D%20%5Cright%29%0A%5C%5C%5C%5C%5C%5C%0A%5Ctheta%3D%5Ccfrac%7Bsin%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B7%5Cpm%5Csqrt%7B53%7D%7D%7B2%7D%20%5Cright%29%7D%7B2%7D)
but anyway, the numerator will give the angles, and θ is just half of each
![\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\ -------------------------------\\\\ sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good} \\\\\\ sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o \\\\\\ \theta=\cfrac{-8.05}{2}\implies \theta=-4.025](https://tex.z-dn.net/?f=%5Cbf%20%5Ctheta%3D%5Ccfrac%7Bsin%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B7%5Cpm%5Csqrt%7B53%7D%7D%7B2%7D%20%5Cright%29%7D%7B2%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Asin%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B7%2B%5Csqrt%7B53%7D%7D%7B2%7D%20%5Cright%29%5Cimplies%20sin%5E%7B-1%7D%287.14%29%5Cimpliedby%20%5Ctextit%7Bgreater%20than%201%2C%20no%20good%7D%0A%5C%5C%5C%5C%5C%5C%0Asin%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B7-%5Csqrt%7B53%7D%7D%7B2%7D%20%5Cright%29%5Cimplies%20sin%5E%7B-1%7D%28-0.14%29%20%5Capprox%20-8.05%5Eo%0A%5C%5C%5C%5C%5C%5C%0A%5Ctheta%3D%5Ccfrac%7B-8.05%7D%7B2%7D%5Cimplies%20%5Ctheta%3D-4.025)
ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025
so the angle is 355.975°
now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°
and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there