We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.
We know that area of rectangle is width times length.
To find the area of the given rectangle we will multiply both side lengths as:
Therefore, the area of the given rectangle would be 
square yards.
3y=8x
Explanation:
If y varies directly with x then
y=c⋅x for some constant of variation c
If (x,y)=(14,23) is a solution to this equation, then
23=c⋅14
→c=23⋅41=83
So
y=83x
or (clearing the fraction)
3y=8x
<span>s = -16t^2 + 88t + 5
Time to reach the maximum height = 88/32
= 2.75 seconds
Maximum height = -16(2.75)^2 + 88 (2.75) +5
= -121 + 242 + 5
= 126 Feet
Range: 5<y<44</span>
(-3 2/3) * (-2 1/4) ...turn to improper fractions
-11/3 * - 9/4 = ....now multiply straight across,and neg. x neg. = pos
99/12 reduces to 33/4 or 8 1/4
Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
