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otez555 [7]
2 years ago
11

What is the maximum number of boxes that can be purchased with $65.00?

Mathematics
2 answers:
oee [108]2 years ago
7 0
How ever much the boxes are
snow_tiger [21]2 years ago
6 0
What is the price of the individual boxes?
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PLEASE HELP!!!!!!!!!! WILL MARK BRAINLIEST ANSWER.
Hatshy [7]
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Hopes this helps! :)
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Green Leaf Lawn Care had 64 customers under contract at the start of the year. The company's owner expects his new radio adverti
cestrela7 [59]

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C. c = 64 + 2w

Step-by-step explanation:

You're starting with 64 customers and you're gaining 2 for each week.

<em>good luck, i hope this helps :)</em>

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Write a fraction that is less than 5/6 and has a denominator of 8
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1/8

Step-by-step explanation:

7 0
3 years ago
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Which of the following is the solution to 4|x+2|&gt;=16. HELP ME RIGHT NOW
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yes

Step-by-step explanation:

4 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
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