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defon
3 years ago
10

Identify the following as Expression or Equationi will give brainliest

Mathematics
2 answers:
malfutka [58]3 years ago
7 0
1) Expression
2) Equation
3) Expression
4) Equation
AnnyKZ [126]3 years ago
3 0
Expression, equation, expression, and equation! ❤️
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Find the value of x in the questions?
tino4ka555 [31]

Answer

10

Step-by-step explanation:

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3 years ago
<-- 50 points No Trolls please
vichka [17]

Answer:

the correct answer is 1 because it looks like they are doing it by odd numbers.

hope this helps :)

Step-by-step explanation:

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3 years ago
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Two angles of a quadrilateral measure 140° and 80°. The other two angles are in a
aliina [53]

Answer:

Step-by-step explanation :

Ratio = 3x : 4x

<h3>Sum of angle of a quadrilateral = 360</h3><h3>Therefore, 140+80+3x+4x = 360</h3><h3>220+7x = 360</h3><h3>7x = 360-220</h3><h3>x= 140/7</h3><h3>x=20</h3><h3>3x= 3×20=60</h3><h3>4x=4×20=80</h3>
7 0
4 years ago
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Me ajudem nessa equação :<br> 10x - 12 + 10= +18 - 20
nirvana33 [79]
10x - 12 + 10 = 18 - 20
10x - 2 = -2
10x = 0
x = 0 
6 0
4 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
4 years ago
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