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3 years ago

help me pls pls pls

Mathematics

2 answers:

valentinak56 [21]3 years ago

3 0

What the guy here is gonna say

pishuonlain [190]3 years ago

3 0

Answer:

33 + p = 43 is the answer

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Three parallel lines are intersected by a transversal. twelve angles are created. one of the angles measures 48° how many of the

lozanna [386]

If there are twelve angles created, almost all of them are congruent. All the sides have to equal 180. If there are three parallel lines they must have 2 angles on each side. 3*2=6, there is a total of six with a measure of 48.

5 0

3 years ago

Read 2 more answers

A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.

Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21$

A doesn't equal 21. On to the next one.

B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2

Everywhere you see x,y,z, you replace with their value.

$1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21$

B also doesn't equal 21. On to the next one...

C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2

Everywhere you see x,y,z you replace with their value.

$1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21$

Both sides of the equation equal 21 which means C is our answer.

7 0

3 years ago

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

astra-53 [7]

Answer:

C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

$p_1=X_1/n_1=1642/4276=0.384$

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

$p_2=X_2/n_2=1415/3908=0.3621$

The difference between proportions is (p1-p2)=0.0219.

$p_d=p_1-p_2=0.384-0.3621=0.0219$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1642+1415}{4276+3908}=\dfrac{3057}{8184}=0.3735$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107$