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sdas [7]
3 years ago
7

50 points!!! Will mark brainliest if correct!! Pls help me!!

Mathematics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

3rd option is correct, give me brainiest

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Factories 5x+10 <br> Somebody please help
jolli1 [7]

Answer:

5(x+2)

Step-by-step explanation:

to factor it we need to find a common term(5) and then we take it out(divide) resulting in the answer abover

5 0
3 years ago
What's the rule? X10 5 25 y 41 21 101
mario62 [17]

It looks to me like      y  =  4x + 1

3 0
3 years ago
A school has 17 tables in the cafeteria. Each table seats 12 students. What is the
Scorpion4ik [409]

Answer: 204 students

Step-by-step explanation: To find  out the greatest number of students that can fit at the 17 tables in the school cafeteria, we simply need to multiply the number of students that can fit at each table by the number of tables.

12 students can fit at 1 table and there are 17 tables.

So we have (12)(17) which is 204.

So the greatest number of students that can be seated din the cafeteria is 204 students.

8 0
3 years ago
Read 2 more answers
Would you please help me with this quiz answer, I will really appreciate if you do. ​
laila [671]

Answer:

a . domain 5,0,7,9,0

range -2,-2,-4,8,2

b. domain 2,4,8,9

range 1,2,4,11

Step-by-step explanation:

<h3>a is not a function</h3>

because function is a relationship in which each domain element occurs only once.

<h3>b is a function</h3>
6 0
3 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos &#10;y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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