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mojhsa [17]
3 years ago
14

Draw a diagram that shows 1/5 times 30 equals 6

Mathematics
2 answers:
MrMuchimi3 years ago
3 0

Total number = 30

1/5 of 30 = 1/5 x 30 = 6

The attached figures show the total number of filled circles in five lines. Each line have “6” filled circles.

So 5 lines having 6 filled circles = 5 x 6 = 30

<span>Every line represents “1/5” of total amount “30”. Which proved that 1/5 of 30 is equal to 6. </span>

Nookie1986 [14]3 years ago
3 0
You cannot draw diagrams on this program or send links
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Jose worked n hours at 8.75 dollars per hour he made a total of $61.25 write an expression that represents the total number of h
Nitella [24]

Answer:

n = P/8.75

Step-by-step explanation:

Jose’s pay (P) depends on the number (n) of hours he works.

P = 8.75n     Divide both sides by 8.75

n = P/8.75

=====

P = $61.25

n = 61.25/8.75

n = 7 h

Jose worked for 7 h.

8 0
3 years ago
Which values of m and b will create a system of equations with no solution? Check all that apply.
Law Incorporation [45]

Answer:

y = -2x + 1

 

Step-by-step explanation:

Then any equation of the form y = -2x + b, b≠1 will create a system with no solution.  Hence the values of m and b are m = -2, b ≠ 1.

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8 0
4 years ago
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Determine whether the following argument is valid or invalid.
prisoha [69]

I think it’s the Law of Syllogism.


8 0
3 years ago
Write an inequality for the graph below
andrezito [222]

Answer:

y > -1/4x + 4

Step-by-step explanation:

First find the equation of the line itself, which is y = -1/4x + 4, then determine if graph shades above the line or below the line. If it shades above which is true in this case, it will be greater than. If it shades below which does not occur in this case, it will be less than. Because the line is dashed and not solid, it will just be greater than or less than.

Therefore y = -1/4x + 4 → y > -1/4x + 4 [Shades above the line, line is dashed].

6 0
3 years ago
Find three consecutive integers such that that product of the first and third is one
Tema [17]

Answer:

n = the first

n + 1 = the 2nd

n + 2 = the 3rd

n(n + 2) - (n + 1) = 10(n + 2) + 1

n2 + 2n - n - 1 = 10n + 20 + 1

n2 - 9n - 22 = 0

(n - 11)(n + 2) = 0

If two factors = 0, at least one must = 0.

n - 11 = 0

n = 11

11,12,13

n + 2 = 0

n = -2

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7 0
3 years ago
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