Explain whether the points (-13,4), (-7,3), (-1,2), (5,1). (11,0), (17, -1) represent the set of all the solutions for the
Nataly [62]
Answer:
ohh this is little bit hard
Step-by-step explanation:
<h2>
Hello!</h2>
The answers are:
The possible values for x in the equation, are:
First option, ![5\sqrt[3]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B3%7D)
Second option, ![\sqrt[3]{375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B375%7D)
<h2>
Why?</h2>
To solve the problem, we need to remember the following properties of the exponents and roots:
![a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}](https://tex.z-dn.net/?f=a%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bn%7D%2Ab%7D%20%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%28a%5E%7Bb%7D%29%5E%7Bc%7D%3Da%5E%7Bb%2Ac%7D)
Then, we are given the expression:
So, finding "x", we have:
![x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}](https://tex.z-dn.net/?f=x%5E%7B3%7D%3D375%5C%5C%5C%5C%28x%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28375%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B375%7D%3D%5Csqrt%5B3%5D%7B125%2A3%7D%3D%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B3%7D%3D5%5Csqrt%5B3%5D%7B3%7D)
Hence, the possible values for x in the equation, are:
First option,
Second option,
Have a nice day!
Answer:
K/(4+9b) = a
Step-by-step explanation:
K = 4a + 9ab
Factor out a on the right hand side
K = a(4 + 9b)
Divide each side by (4+9b)
K/(4+9b) = a(4 + 9b)/(4+9b)
K/(4+9b) = a
Answer:
y=12
Step-by-step explanation:
y=2x ,so 2x=8x-x^2
x^2=8x-2x
x^2=6x
x^2/x=6x/x
x=6
y=2x ,2(6)
y=12
Answer:
4,5,6
Step-by-step explanation:
*The sign of ≥ means that it must be greater or equal to 10 in this case
1). 3 isn't a possible solution due to 9 being less than 10
3+6_10
9_10
9<10
2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10
4+6_10
10_10
10=10
3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10
5+6_10
11_10
11>10
4).6 is a possible solution due to the sum of 6 and 6 being larger than 10
6+6_10
12_10
12>10
Hope this helped! (:
