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pashok25 [27]
3 years ago
13

two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they

charged a total of $1600. what are the rate charged per hour by each mechanic. if the sum of the two rates are $215 per hour.
Mathematics
1 answer:
Lerok [7]3 years ago
7 0
Let's make,
mechanic #1's rate = x
mechanic #2's rate = y

* Their rate is dollars per hour ($/hr)

mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1

and mechanic #2 worked for 5 hours
5y = money earned by mech#2

together they charged a total of $1150. So the amount of money earned by both mechanics.

20x + 5y = 1150

the sum of the two rates was $95 per hour.

x + y = 95

which means
x = 95 - y

plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.

20(95 - y) + 5y = 1150

solve for y

1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr

Now use this to solve for x

x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr

mech#1 charged 45$/hr
mech #2 charged 50$/hr
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4.36*10^-^1

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The Daily Info charges a fee of plus per week to run an ad. The People's Paper charges per week. Write an inequality to represen
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Complete question :

The Daily Info charges a fee $650 of plus $80 per week to run an ad. The People's Paper charges $145 per week. Write an inequality to represent the number of weeks an ad must run for the total cost at the Daily Info to be less expensive than the cost at the People's Paper. Let w be the number of weeks the ad runs in the paper

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Step-by-step explanation:

Given that :

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The People's Paper total cost:

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