Answer: √(f^2 - 2f + 1) = a
Step-by-step explanation:
We have that:
f^2+g^4-2f+1 = a^2+(g^2)^2
And we want to find the value of a, so we should isolate it.
f^2 + g^4 - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4
where i used that (x^y)^z = x^(y*z)
We can remove the term g^4 in both sides of the equation and get:
f^2 - 2f + 1 = a^2
now we can apply the square rooth to both sides and get
√(f^2 - 2f + 1) = a
So we just found the value of a.
Answer:

Step-by-step explanation:
Volume of a cone:

Take
as 3, as mentioned in the question
'r' is 'radius' ⇒ {diameter is given so divide by 2: 12/2 = 6}
'h' is 'height'



{multiply 108 with 5 and then divide the answer by 3}
× 



Answer:
Domain : {x | all real numbers} ; Range: {y | y > 0}
Step-by-step explanation:
The function can be written as :
![f(x)=\sqrt[\frac{2}{3}]{108^{2\cdot x}}\\\\\implies f(x)=(108)^{(\frac{3}{2})^{2\cdot x}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5Cfrac%7B2%7D%7B3%7D%5D%7B108%5E%7B2%5Ccdot%20x%7D%7D%5C%5C%5C%5C%5Cimplies%20f%28x%29%3D%28108%29%5E%7B%28%5Cfrac%7B3%7D%7B2%7D%29%5E%7B2%5Ccdot%20x%7D%7D)
Now, since x is exponent so it can take any real values. So, its domain of f(x) is all real numbers
But value of f(x) can not be less than 1 because for x = 0 the value of f(x) is 1 and also for any values of x, the value of f(x) can never be less than 1
So, Range of f(x) is all real numbers greater than 0
Hence, Domain and Range of f(x) is given by :
Domain : {x | all real numbers} ;
Range: {y | y > 0}
Washington had 143 hits and Sanchez has 107 hits
Answer: you do the one
Step-by-step explanation:
Yeah