Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055
I think the answer is A because the balance after 4 years is not on their and so we are trying to find the balance after three years. And after 3 years the balance is 805
Answer:
10
Step-by-step explanation:
We can write the equation 38=4y-2 because LZ and DO are equivalent
Isolate x:
38=4y-2
38+2=4y-2+2 (add 2, addition property of equality)
40=4y
40/4=4y/4 (divide by 4, division property of equality)
10=y