Help me out please???

In our class, there are 14 female and 11 male students. a. Pick one student randomly, what is the probability you get a female s

Reika [66]

Answer:

a) 56% probability you get a female student.

b) 30.33% probability that both are female

c) 43.52% probability that you get 2 female and one male

d) 18.26% probability that you get 1 female and 3 male

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in whih the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

a. Pick one student randomly, what is the probability you get a female student?

Desired outcomes:

1 female student from a set of 14. So

$D = C_{14,1} = \frac{14!}{1!13!} = 14$

Total outcomes:

1 student from a set of 25. So

$T = C_{25,1} = \frac{25!}{1!24!} = 25$

Probability:

$P = \frac{D}{T} = \frac{14}{25} = 0.56$

56% probability you get a female student.

b. Pick two students randomly, what is the probability that both are female?

Desired outcomes:

2 female students, from a set of 14. So

$D = C_{14,2} = \frac{14!}{2!12!} = 91$

Total outcomes:

2 students from a set of 25. So

$T = C_{25,2} = \frac{25!}{2!23!} = 300$

Probability:

$P = \frac{D}{T} = \frac{91}{300} = 0.3033$

30.33% probability that both are female

c. Pick three students randomly, what is the probability that you get 2 female and one male?

Desired outcomes:

2 female students, from a set of 14, and one male student, from a set of 11. So

$D = C_{14,2}*C_{11,1} = \frac{14!}{2!12!}*\frac{11!}{1!10!} = 1001$

Total outcomes:

3 students from a set of 25. So

$T = C_{25,3} = \frac{25!}{3!22!} = 2300$

Probability:

$P = \frac{D}{T} = \frac{1001}{2300} = 0.4352$

43.52% probability that you get 2 female and one male

d. Pick four students randomly, what is the probability that you get 1 female and 3 male?

Desired outcomes:

1 female student, from a set of 14, and 3 male students, from a set of 11.

$D = C_{14,1}*C_{11,3} = \frac{14!}{1!13!}*\frac{11!}{8!3!} = 2310$

Total outcomes:

4 students from a set of 25. So

$T = C_{25,4} = \frac{25!}{4!21!} = 12650$

Probability:

$P = \frac{D}{T} = \frac{2310}{12650} = 0.1826$

18.26% probability that you get 1 female and 3 male

5 0

2 years ago

25 POINTS! Answer needed ASAP! You WILL be named Brainiest!

bija089 [108]

Answer:

We need to send more than 400 messages for Plan B to be the better option.

Step-by-step explanation:

Plan A

The cost is a flat fee of 30 plus 10 cents per message

Cost= 30 +.10m

Plan B

The cost is a flat fee of 50 plus 5 cents per message

Cost = 50 +.05m

We want cost of B to be less than cost A

30 +.10m > 50 +.05m

Subtract .05m from each side

30 +.10m- .05m > 50 +.05m-.05m

30 +.05m > 50

Subtract 30 from each side

30-30 +.05m > 50-30

.05m > 20

Divide each side by .05

.05/.05m > 20/.05

m > 400

We need to send more than 400 messages for Plan B to be the better option.

4 0

3 years ago

four pieces of pie were eaten from a pie cut into equal parts. The 5 pieces that remained created an angle that measured 200°. W

Morgarella [4.7K]

Step-by-step explanation:

The 5 pieces that remained created an angle that measured 200 degree means that the 4 pieces made 360-200 degrees 160o.

If all four made 160 then each has to be 160/4 = 40o

200/5 also gives you 40 (the five remaining)

360/9 would also give you 40 9the 5 remaining and the 4 eaten)

I hope this helps

6 0

3 years ago

Divide the rational expressions. p2−p−22p2+3p+1÷p2−3p+2p2+5p−6 Enclose numerators and denominators in parentheses. For example,

timofeeve [1]

Given:

$\frac{\frac{p^2-p-2}{2p^2+3p+1}}{\frac{p^2-3p+2}{p^2+5p-6}}$

Simplify in the from of numerators and denominators.

$\frac{p^2-p-2}{2p^2+3p+1}\times\frac{p^2+5p-6}{p^2-3p+2}$

solve the inequality is:

$undefined$

6 0

11 months ago

What is the square root of 1675

liubo4ka [24]

40.9267 is the square root

7 0

2 years ago

Read 2 more answers