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3 years ago

–3x – 3 < –63 This is rlly needed.

Mathematics

1 answer:

NISA [10]3 years ago

6 0

-3x -3 < -63 subtract the 3 first
-3x < -60 then divide the -3 from both sides
x < 20 is your answer

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Each month, a phone company charges $30 talk time plus $0.50 for each additional minute.

OlgaM077 [116]

Answer:

Step-by-step explanation: If 1 minutes of talk = 30 and texting = 30

and each additional minute of talk = 0.50

then the bill would be (for C = total cost)

C = 20+30+(0.45 • x)

C = 50 + 0.45x

6 0

2 years ago

Read 2 more answers

Geometric Shapes - Part 1

Softa [21]

Answer:

x = 54, so the vertical angles are 110°.

Step-by-step explanation:

$2x + 2 = 3x - 52$

$2 = x - 52$

$x = 54$

$2(54) + 2 = 108 + 2 = 110$

$3(54) - 52 = 162 - 52 = 110$

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2 years ago

How do I find the perimeter of a polygon?

noname [10]

Add up the lengths of the several sides of the polygon.

Examples: The perimeter of a triangle is the sum of the lengths of the 3 sides.

The perimeter of a hexagon is the sum of the lengths of the 6 sides.

And so on.

I highly recommend drawing any polygon whose perimeter you wish to calculate.

6 0

3 years ago

Rajan climbed to a height of 10 ft from the bottom of a climbing wall. He then climbed up an additional 5 ft. What must he do to

max2010maxim [7]

I'm assuming this is a Pythagorean theorem problem. If so the answer would be √125

4 0

3 years ago

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13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

3 years ago