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s344n2d4d5 [400]
3 years ago
7

Options are:

Mathematics
1 answer:
frosja888 [35]3 years ago
6 0

Answer:

Step-by-step explanation:

Apply the slope formula to be sure. The slope formula is

m=\frac{y_2-y_1}{x_2-x_1}

Filling in with our coordinates gives us:

m=\frac{-2-10}{-2-4}=\frac{-12}{-6}=2

The slope is 2. If you don't want to use the slope formula you could just look at the line and pick 2 points the line goes through and use a slope triangle, but that's a bit more difficult to explain without the benefit of being there to point out the idiosyncrasies of it.

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Maria makes beaded necklaces. She charges a rate of $0.75 per inch in length plus $0.25 per bead as shown in the expression, whe
sergiy2304 [10]
16x+60y
16(.75)+60(.25)
12+15=27
maria would charge $27 for this necklace
3 0
4 years ago
Read 2 more answers
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
Which of the following is an equation of the line through (2,3) and (-1,-12)
ahrayia [7]

Answer:

y = 5x - 7

Step-by-step explanation:

Using the equation of a line with two points

y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1

Giving two points

( -4 , 10)(16 , -2)

x_1 = -4

y_1 = 10

x_2 = 16

y_2 = -2

Using the above formula

y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1

-12 - 3 / -1 - 2 = y - 3 / x - 2

-15/-3 = y - 3 /x - 2

Cross multiply

-15(x - 2) = -3(y - 3)

-15x + 30 = -3y + 9

-15x + 30 + 3y - 9 = 0

-15x +30 - 9 + 3y = 0

-15x + 21 + 3y = 0

3y = 15x - 21 ( following y = mx + C

Dividing through by 3 to find y

3y/3 = 15x -21 / 3

y = 15x - 21 / 3

We can still separate

y = 15x / 3 - 21/3

y = 5x - 7

Therefore, the equation of the line is

y = 5x - 7

6 0
3 years ago
What is the root of this equation? <br>2x^2 - 4x + 9 = 0​
faust18 [17]

Answer:

x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)

Step-by-step explanation:

Solve for x:

2 x^2 - 4 x + 9 = 0

Divide both sides by 2:

x^2 - 2 x + 9/2 = 0

Subtract 9/2 from both sides:

x^2 - 2 x = -9/2

Add 1 to both sides:

x^2 - 2 x + 1 = -7/2

Write the left hand side as a square:

(x - 1)^2 = -7/2

Take the square root of both sides:

x - 1 = i sqrt(7/2) or x - 1 = -i sqrt(7/2)

Add 1 to both sides:

x = 1 + i sqrt(7/2) or x - 1 = -i sqrt(7/2)

Add 1 to both sides:

Answer:  x = 1 + i sqrt(7/2) or x = 1 - i sqrt(7/2)

4 0
4 years ago
Use the grouping method to factor the polynomial below completely. x3 - 3x2 + 5x - 15
LUCKY_DIMON [66]

Answer:

(x²+5) (x-3)²

Step-by-step explanation:

x³ - 3x² + 5x - 15

x²(x-3) + 5(x-3)

(x²+5) (x-3)²

4 0
3 years ago
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