Answer:
this is what i found
Step-by-step explanation: Multiply k and 9
Multiply k and 1
The k just gets copied along.
The answer is k
k
9*k evaluates to 9k
Multiply m and 9k
Multiply the m and k
Multiply m and k
The m just gets copied along.
The k just gets copied along.
The answer is mk
mk
9*k*m evaluates to 9mk
Multiply u and 9mk
Multiply the u and mk
Multiply u and mk
The u just gets copied along.
The m just gets copied along.
The k just gets copied along.
The answer is umk
umk
9*k*m*u evaluates to 9umk
Multiply l and 9umk
Multiply the l and umk
Multiply l and umk
The l just gets copied along.
The u just gets copied along.
The m just gets copied along.
The k just gets copied along.
The answer is lumk
lumk
9*k*m*u*l evaluates to 9lumk
Multiply t and 9lumk
Multiply the t and lumk
Multiply t and lumk
T
Your answer is 89 since 4*10=40)+5*5=25)+2*12=24, add all the results up and get 89.
Answer:
73.5
Step-by-step explanation:
Part/whole=percent/100
?/500=2.1%/100
500 divided by 100 is 5, so 2.1% times 5 is 10.5, which is the amount of interest made per year.
So, 10.5 times 7 is 73.5
Answer:

Step-by-step explanation:
we know that
The exponential function is of the form

where
a is the initial value
b is the base
In this problem we have
a=200 birds
b=100%+4%=104%=104/100=1.04
substitute

Let change of variables

where
b is the amount of birds in the flock
d is the number of days since the 200 birds started
Answer:
1/6
Step-by-step explanation:
We want to find how long it takes for the bacteria to lose half its size. We can do this by taking one point of the bacteria and finding how long it takes to go to half its size. When t=0, 9300 * (1/64)^t = 9300 * 1 = 9300 as anything to the power of 0 is 1. Therefore, we can solve for t when the end result of the bacteria is 9300/2= 4650, making our equation
4650 = 9300 * (1/64)^t
divide both sides by 9300
1/2 = (1/64)^t
First, we can tell that 2^6 = 64*. Because of this, we can say that (1/2)^6 = 1^6/2^6 = 1/64, so (1/64)^(1/6) = 1/2. We know this because
(1/2)^6 = 64
take the 6th root of both sides
(1/2) = (64)^(1/6)
. This means that t=1/6, so the bacterial culture loses 1/2 of its size every 1/6 seconds
* if this is harder to figure out, e.g. 3 and 729, we can plug (log₃729) into a calculator