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3 years ago

6

Plz plz plz help me quickly I’ll give brainlist!!!!!!!!!!

1 answer:

Nesterboy [21]3 years ago

5 0

Answer:

$16.60 ,and you saved $66.40

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Bob is having a party and wants to order some cakes.

Dmitry [639]

Answer: There isn't a possible way you can really answer this question because I don't know how much one piece cost in the first place , but if I had to guess I would say around 50-80 dollars for a cake is enough for 57 guests.

explanation: I say this because I know usually cakes for a decent amount of people are around 50-80 dollars.

7 0

3 years ago

Name one possible cross section of a sphere

Lisa [10]

A "cross section" is basically the two-dimensional face that you get when you cut a three-dimensional figure a certain way. For example, imagine you're buttering your bread. When you cut a pat of butter off, what shape is left on the butter? A square!

So, imagine cutting a ball in half. What shape is left? A circle!

Answer: circle

8 0

3 years ago

Read 2 more answers

(15+6) divde 3 Evalute the expression

Tom [10]

Answer:

(15+6)/3

21/3=7

5 0

3 years ago

Read 2 more answers

What is the difference?

Whitepunk [10]

Answer:

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

Step-by-step explanation:

Given

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

Required

Calculate the difference

We start by factorizing the denominator of both fractions

$\frac{x}{x^2-2x-15} - \frac{4}{x^2+2x-35}$

$\frac{x}{x^2+3x - 5x -15} - \frac{4}{x^2+7x - 5x-35}$

$\frac{x}{x(x+3) - 5(x +3)} - \frac{4}{x(x+7) - 5(x+7)}$

$\frac{x}{(x-5) (x +3)} - \frac{4}{(x-5)(x+7)}$

Take LCM

$\frac{x(x+7) - 4(x +3)}{(x-5) (x +3)(x+7)}$

Open Brackets

$\frac{x^2+7x - 4x -12}{(x-5) (x +3)(x+7)}$

$\frac{x^2+3x -12}{(x-5) (x +3)(x+7)}$

This can't be simplified any further;

4 0

3 years ago

Explain whether or not the following equation is a quadratic function in vertex form. y = 4(x - 2)^2 + 6.

steposvetlana [31]

Answer:

Yes, the following equation is a quadratic function in vertex form

Step-by-step explanation:

we know that

The <u>quadratic function</u> of the vertical parabola into <u>vertex form</u> is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex of the parabola

If the <u>coefficient</u> a is > 0 ----> the parabola open upward (vertex is a minimum)

If the coefficient a is < 0 ----> the parabola open downward (vertex is a maximum)

in this problem we have

$y=4(x-2)^{2} +6$

The <u>squared term</u> contain the x-coordinate of the vertex

$h=2$

The <u>constant term</u> is the y-coordinate of the vertex

$k=6$

The vertex is the point (2,6)

The coefficient is equal to

$a=4$ ----> open upward (vertex is a minimum)

6 0

3 years ago