21x-9+6y
combining terms: 4x+17x=21x
To solve this problem, let us first assign some
variables. Let us say that:
x = pigs
y = chickens
z = ducks
From the problem statement, we can formulate the
following equations:
1. y + z = 30 --->
only chicken and ducks have feathers
2. 4 x + 2 y + 2 z = 120 --->
pig has 4 feet, while chicken and duck has 2 each
3. 2 x + 2 y + 2 z = 90 --->
each animal has 2 eyes only
Rewriting equation 1 in terms of y:
y = 30 – z
Plugging this in equation 2:
4 x + 2 (30 – z) + 2 z = 120
4 x + 60 – 2z + 2z = 120
4 x = 120 – 60
4 x = 60
x = 15
From the given choices, only one choice has 15 pigs. Therefore
the answers are:
She has 15 pigs, 12 chickens, and 18 ducks.
Answer:
see explanation
Step-by-step explanation:
To find the zeros let p(x) = 0 , that is
(x² - 1)(x² - 5x + 6) = 0
Factorise each factor
x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)
x² - 5x + 6 = (x - 2)(x - 3), thus
(x - 1)(x + 1)(x - 2)(x - 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x - 2 = 0 ⇒ x = 2
x - 3 = 0 ⇒ x = 3
The zeros are x = ± 1, x = 2, x = 3
Answer:
I think it's a or b but if I get you this wrong I'm sorry try with a first then b again I aploizge if I get you this wrong.
Answer:
to the full amount
Step-by-step explanation:
