<h2>Hey mate,</h2><h3>I have attached the answer below</h3><h3>Hope it will help you...</h3>
Answer:
Pls....can mark brainliest
Y=-2x^2+2x-4. Should be correct
Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...
... 30-60-90: 1 : √3 : 2
... 45-45-90: 1 : 1 : √2
The long side of ΔMDX is 10√3, so the other two sides are
... MX = MD(√3/2) = 15
... DX = MD(1/2) = 5√3
The short side of ΔMNX is MX = 15, so the other two sides are
... NX = MX(1) = 15
... MN = MX(√2) = 15√2
Then the perimeter of ΔDMN is ...
... P = DM + MN + NX + XD
... P = 10√3 +15√2 + 15 + 5√3
... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN
Big marbles = 45red 3/4 blue
Small marbles = 2/5 red 3/5 blue 24 more small blue mabrles than red marbles
What percentage of the marbles are big marbles
First of all lets working out the missing values:
Big Marbles, 45 red, 3/4 blue. If 45 red is 1/4, then 135 (45*3) is 3/4.
Big Marbles, 45 red, 135 blue = 180 in total
For the small marbles, we do some logical thinking:
If red is 2/5, and blue is 3/5. And blue has 24 more than red.
That means 24 = 1/5
So in total there are 120 small marbles (24*5)
There are 180 big marbles
We add these together, 120 + 180 = 300 marbles
180 / 300 = 0.6 = 60%
^ Divide the big marbles by the number of total marbles
60% of the marbles are big marbles
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