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creativ13 [48]
3 years ago
14

What is the answer to this problem

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0
B, -3x+15=23 is the answer
IRINA_888 [86]3 years ago
7 0
The answer is B.
How?
Take the original equation and multiply the parenthesis by 3:
3x+15-6x=23
Now, unite the two x terms like this
3x-6x+15=23
Now, combine them by doing 3-6 (which is -3), and making that the coefficient on x:
-3x+15=23
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What’s the derivative of (2x+9)^3
larisa86 [58]

If f(x) = (2x+9)^3, f '(x) = 3(2x+9)^2*(2), or f '(x) = 6(2x+9)^2.  Here we used the power rule with chain rule to find the derivative.

8 0
3 years ago
8 1/5 - 2 1/3<br> I need to find what this answer is quick! please help me!
kondaur [170]
The answer is 5 13/15 or atleast according to calculator.net (the website used in the picture) :)

5 0
3 years ago
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Find the slope of a line parallel to the given line. y=4/5x+5
xeze [42]

Answer:

y = 4/5x

Step-by-step explanation:

Her ya go!

3 0
3 years ago
Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o
NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so \pi = 0.8.

(a) What is the probability she gets an A?

There are four problems, so n = 4

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find P(X \geq 3)

P(X \geq 3) = P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096

P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096

P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so n = 3

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find P(X \geq 2)

P(X \geq 3) = P(X = 2) + P(X = 3)

P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384

P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512

P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0
3 years ago
I need help please and thank you
fomenos

Answer:

37.7 feet.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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