All categories

3 years ago

PLEASE HELP WILL MARK BRAINLIEST HELP QUICK

Mathematics

2 answers:

schepotkina [342]3 years ago

8 0

1.) V~16,964.6 m^3
2.) radius=6 in
Good luck

frosja888 [35]3 years ago

6 0

Answer:

first one is 16,956m^2 second one is 6 in

You might be interested in

Harriet has some five dollar bills and some one dollar bills She has 20 bills. The value of the bills is $72 write and solve a s

boyakko [2]

So let's say
x=number of five dollare bills
y=number of 1 dolar bills

20 bills total
x+y=20

totla is 72 monies
72=5 times x+1 times y=5x+1y=5x+y
solve

x+y=20
5x+y=72
from here you could do 2 things: go to option 1 (longer) or option 2 (shorter)

1.

x+y=20
subtract x from both sides
y=20-x

5x+y=72
subtract 5x from boths ides
y=72-5x
subsitute

y=20-x=y=72-5x
20-x=72-5x
add 5x to both sides
20+4x=72
subtract 20 from both sides
4x=52
divide both sides by 4
x=13

subsitute
x+y=20
13+y=20
subtract 13
y=7

2.

another way is when you got 5x+y=72 and x+y=20
you negative the second equaiton and add to th efirst
I know it sounds like voodo at first but it works
-(x+y=20)=-x-y=-20
add

5x+y=72
<u>-x-y=-20 +</u>
4x+0y=52
4x=52
divide both sides by 4
x=13

subsitute
x+y=20
13+y=20
subtract 13
y=7

8 0

4 years ago

The bank does not charge a fee for cashing checks as long as members keep a balance, b, of at least $500 in their checking accou

IrinaVladis [17]

Answer:

b ≥ 500

Step-by-step explanation:

since the balance has to be at least 500, b has to be grater than or equal to 500, so b ≥ 500

7 0

3 years ago

Read 2 more answers

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

4 years ago

Read 2 more answers

Whats mc mean in mc2

Grace [21]

Answer:

the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.

Step-by-step explanation:

5 0

3 years ago

Please help!.......

larisa86 [58]

(f+g) means add the expressions together. combine like terms.
$5 {x}^{2} + 3 {x}^{2} = 8 {x}^{2}$
$- 2x + x = - x$
there is no other constant term so the -4 stays as is.

4 0

4 years ago