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IceJOKER [234]
2 years ago
6

Greg is 5 times Sam's age. Greg is 15 years old. Write an equation to represent "s", Sam's age​

Mathematics
1 answer:
vfiekz [6]2 years ago
5 0

Answer:

The equation to represent Sam's age​ is 15 ÷ 5 = s

s = 3

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The equation of the line is ?
larisa86 [58]

Answer:

Y = mx + b

y = how far up

x = how far along

m = Slope or Gradient (how steep the line is)

b = value of y when x=0

7 0
2 years ago
Can someone please help me?? Im not quite sure how to get this answer.
nekit [7.7K]

Answer:

C. 54π + 20.25√3 cm²

Step-by-step explanation:

The shaded area can be split into two areas: a sector and an isosceles triangle.

Area of a sector is:

A = (θ/360°) πr²

where θ is the central angle and r is the radius.

Area of an isosceles triangle can be found with SAS formula:

A = ½ ab sin θ

where a and b are two sides of a triangle and θ is the angle between them.

In this case, r = a = b = 9 cm.  The central angle of the sector is 240°, and the vertex angle of the triangle is 120°.  Therefore, the total area is:

A = (240°/360°) π (9 cm)² + ½ (9 cm) (9 cm) sin 120°

A = 54π + 20.25√3 cm²

5 0
3 years ago
HOURS MILES WALKED Y/X 2 3 4 6 6 a 8 12 k: what is the answer​
Rasek [7]

Answer:

12 number for theanswer of that question answer

7 0
2 years ago
Mary bought two doughnuts and a carton of milk for $2.87. The carton of milk was $1.29. How much is one doughnut?
cupoosta [38]

Answer:

1000000000000000000000000000

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Do well-rounded people get fewer colds?
asambeis [7]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if people with less social contact get more colds than people who are involved in a variety of social activities.

For this, a sample of 276 healthy men and women was taken.

n₁= 96 had few social outlets

n₂= 105 had six or more activities

These two groups were exposed to the cold virus and the following proportions of individuals that got sick were obtained:

p'₁= 0.62 (62% of the people with few social outlets got sick)

p'₂= 0.35 (35% of the people with six or more activities got sick)

The study variables are X₁: number of people with few social outlets that got sick after being exposed to the cold virus, in a sample of 96, and X₂: number of people with six or more activities that got sick after being exposed to the cold virus, in a sample of 105.

You have to construct a 99% CI for the difference these two populations since there is no specific order given I'll estimate: p₁ - p₂

(p'₁ - p'₂) ± Z_{1-\alpha /2} * \sqrt{\frac{p'_1(1-p'_1)}{n_1} +\frac{p'_2(1-p'_2)}{n_2} }

Z_{1-\alpha /2}= Z_{0.995}= 2.586

(0.62-0.35) ± 2.586 \sqrt{\frac{0.62*0.38}{96} +\frac{0.35*0.65}{105} }

[0.094; 0.045]

With a 99% confidence level, you'd expect that the difference between the proportion of people with few social outlets that got sick and the proportion of people with six or more social activities that got sick after being exposed to the cold virus.

I hope it helps!

8 0
2 years ago
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