Answer:
The right solution is:
(a) $1,940
(b) $2,813
Step-by-step explanation:
Given:
Invoice amount
= $8,400
Discount 1
= 33.33%
Discount 2
= 12.5%
So,
The net payable amount will be:
= ![8400\times [1 - \frac{100}{300} ]\times [1 - \frac{12.5}{100} ]](https://tex.z-dn.net/?f=8400%5Ctimes%20%20%5B1%20-%20%5Cfrac%7B100%7D%7B300%7D%20%5D%5Ctimes%20%5B1%20-%20%5Cfrac%7B12.5%7D%7B100%7D%20%5D)
= 
= 
($)
Now,
(a)
Amount paid will be:
= 
= 
($)
Balance still to be paid will be:
= 
= 
($)
(b)
Amount paid will be:
= 
= 
= 
($)
Balance still to be paid will be:
= 
($)
Thus the above solution is the appropriate one.
You cannot rely on the drawing alone to prove or disprove congruences. Instead, pull out the info about the sides and angles being congruent so we can make our decision.
The diagram shows that:
- Side AB = Side XY (sides with one tick mark)
- Side BC = Side YZ (sides with double tickmarks)
- Angle C = Angle Z (similar angle markers)
We have two pairs of congruent sides, and we also have a pair of congruent angles. We can't use SAS because the angles are not between the congruent sides. Instead we have SSA which is not a valid congruence theorem (recall that ambiguity is possible for SSA). The triangles may be congruent, or they may not be, we would need more information.
---------------
So to answer the question if they are congruent, I would say "not enough info". If you must go with a yes/no answer, then I would say "no, they are not congruent" simply because we cannot say they are congruent. Again we would need more information.
Answer: f(n+1) = (n - 1)/(n + 2)
Explanation:
f(x) = (x - 2)/x+1
Find f(n+1) simply replace x by (n+1)
f(n+1) = (n + 1 - 2)/(n + 1 + 1)
= (n - 1)/(n + 2)
Answer:
49
Step-by-step explanation:
First multiply 3 x 5.Which will give you 15.Then add 34 and 15 which will give you 49.
Answer:
Mean, E(x) = 0.17
Variance, V(x) = 0.12
Step-by-step explanation:
90% contains no defective bulbs, P(X=0) = 0.9
5% contain one defective bulbs, P(X=1) = 0.05
3% contain two defective bulbs, P(X=2) = 0.03
2% contain three defective bulbs, P(X=3) = 0.02
The mean for the number of defective bulbs:
Variance for the defective bulbs:
V(x) = 0.29 - 0.17
V(x) = 0.12
