A(b-c)=d
Ab-Ac=d
-Ab -Ab from both sides
-Ac=d-Ab
divide -A
c=d-Ab over -A and the -A's should cancel so it should be c=db <span />
You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
V=720ft³
Step-by-step explanation:
V=whl=4·20·9=720ft³
happy to help
Answer:
5
Step-by-step explanation:
3x5x7x9=945
9 is in the hundreds place
4 is in the tens
which means 5 must be in the ones
Volume of a prism= 24,786 ft³
