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Nady [450]
2 years ago
13

BELP ME WITH THIS PLZ!!!!!!

Mathematics
1 answer:
kati45 [8]2 years ago
3 0

Answer:

The entire area of the sailboat is 60cm²

Step-by-step explanation:

You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.

In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.

Because the two triangles can be put together to form a single triangle, we don't need to measure them independently.  We can simply take the total length of their bases, multiply it by their height, and divide by two.  This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.

(2cm + 3cm) × 6cm

= 5cm × 6cm

= 30cm²

The rectangle's area is of course equal to its width times its height, so we can say:

2.5cm × 12cm

= 30cm²

The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²

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I need help please and thank you
Brums [2.3K]

Well I THINK triangle ABC is just a stretched out version of triangle DEF.

To find the area of a triangle, you multiply base and height, and divide by 2.

Area of DEF is 6, so that means that (4 * x)/2 = 6.

6*2 = 12....

4 * x = 12........

4 * 3 = 12.

x = 3.

Comparing DEF to ABC: ABC's base is 3 times as long as DEF's. So that means the height must be three times as long.

3*3 = 9.

(12 * 9)/2 =54

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3 years ago
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q=5n+5z\ \ \ \ \ \ \ |subract\ 5z\\\\q-5z=5n\ \ \ \ \ \ \ |divide\ by\ 5\\\\n=\frac{q-5z}{5}\\\\Answer\ is\ n=\frac{q-5z}{5}
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3 years ago
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How to create every number from 1-50 and I you could only use numbers 1,2,3,4
sergey [27]
1, 2, 3, 4, 1+4, 2+4, 3+4, 4+4, 4+4+1, 4+4+2, 11, 12, 13, 14, 14+1, 14+2, 14+3, 14+4, 14+4+1, 14+4+2, 21, 22, 23, 24, 24+1, 24+2, 24+3, 24+4, 24+4+1, 24+4+2, 31, 32, 33, 34, 34+1, 34+2, 34+3, 34+4, 34+4+1, 34+4+2 ,41,42, 43, 44, 44+1, 44+2, 44+3, 44+4, 44+4+1, 44+4+2
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3 years ago
Find the length of the tangent segment AB to the circles centered at O and O' whose radii are a and b respectively when the circ
bixtya [17]

Answer:

AB=2\sqrt{ab}

Step-by-step explanation:

From figure,

OA=a,  \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)

In triangle OO'D

  (OO')^2=(OD)^2+(O' D)^2

\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}]

Hence, AB=2\sqrt{ab}

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3 years ago
HELP ILL GIVE BRAINLIEST
SVETLANKA909090 [29]

Answer:

\huge\boxed{\bf\:c = \frac{11}{4}}

Step-by-step explanation:

4c + 2c = 4c + \frac{11}{2}

Cancel 4c on both the sides of the equation.

2c = \frac{11}{2}

Bring the 2 in the denominator of 11/2 to the left hand side of the equation.

2*2c = 11\\4c = 11

Bring 4 to the right hand side if the equation.

\boxed{\bf\:c = \frac{11}{4}}

\rule{150pt}{2pt}

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