Answer:
The upper endpoint of the 99% confidence interval for population proportion is 0.13.
Step-by-step explanation:
The confidence interval for population proportion is:
<u>Given:</u>
<em>n</em> = 1000
= 0.102
*Use the standard normal table for the critical value.
Compute the 99% confidence interval for population proportion as follows:
Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.
Answer:
Depends
Step-by-step explanation:
Depends on how many questions you missed. I'm going to assume that you mean you somehow missed every question. So, 86% - 25% would be 46%.
Answer:
x = -6
Step-by-step explanation:
The value of x never changes, no matter what the value of y is, so x = -6 describes every point on the line.
I don’t have enough info to solve your problem
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data:
Number of Home alone movies (X)
Watched probability, p(x)
X : ___ 0 ____ 1 ____ 2 ____ 3 ___ 4 ___ 5
P(x) : _0.15 __ 0.42 __0.32 __? ___0.02 _0.01
a. Write the event "the student has seen 3 Home Alone movies" using probability notation. Then find this probability.
P(x = 3)
Since Σp(x) = 1
P(x =3) = 1 - (p(0)+p(1)+p(2)+p(4)+p(5))
P(x = 3) = 1 - (0.15 + 0.42 + 0.32 + 0.02 + 0.01)
P(x = 3) = 1 - 0.92
P(x = 3) = 0.08
b. Explain in words what P(X > 3) means. What is this probability?
P(x > 3) is the probability they a randomly chosen student has watched more than 3 home alone movies.
P(x > 3) = p(4) + p(5)
P( x > 3) = 0.02 + 0.01 = 0.04
d. Calculate and interpret the expected value of X.
E(X) = [Σ(X * p(x)]
(0*0.15) + (1*0.42) + (2*0.32) + (3*0.08) + (4*0.02) + (5*0.01) = 1.43
The avereage number of home alone movies watched is 1.43
