Check the picture below.
let's notice that the base of the pyramid is triangle with a base of 5 and an altitude of 4, so it has an area of (1/2)(5)(4).
![\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=\stackrel{\textit{area of its}}{base}\\ h=height\\[-0.5em] \hrulefill\\ B=\frac{1}{2}(5)(4)\\ h=8 \end{cases}\implies V=\cfrac{1}{3}\left( \cfrac{1}{2}(5)(4) \right)(8)\implies V=\cfrac{1}{3}(10)(8) \\\\\\ V=\cfrac{80}{3}\implies V=26\frac{2}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20pyramid%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B1%7D%7B3%7DBh~~%20%5Cbegin%7Bcases%7D%20B%3D%5Cstackrel%7B%5Ctextit%7Barea%20of%20its%7D%7D%7Bbase%7D%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20B%3D%5Cfrac%7B1%7D%7B2%7D%285%29%284%29%5C%5C%20h%3D8%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B1%7D%7B3%7D%5Cleft%28%20%5Ccfrac%7B1%7D%7B2%7D%285%29%284%29%20%5Cright%29%288%29%5Cimplies%20V%3D%5Ccfrac%7B1%7D%7B3%7D%2810%29%288%29%20%5C%5C%5C%5C%5C%5C%20V%3D%5Ccfrac%7B80%7D%7B3%7D%5Cimplies%20V%3D26%5Cfrac%7B2%7D%7B3%7D)
Answer:
it is very simple, is you are given the co-ordinates for the graph plot them.
Answer:
6 tens
Step-by-step explanation:
you have to do 60 divided by ten, and I know that there is a remaining three, but the question is how many tens, so it is 6
The numbers are -10, -9, and -8.
Answer:
Absolute value;
The non-negative value of x(in your case -19) without regard to its sign.
Basically how far in distance x(in your case -19) is away from 0.
|–19| = <u>19</u>
