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3 years ago

Just help.................................thanks

Mathematics

2 answers:

alexgriva [62]3 years ago

5 0

Answer:

Step-by-step explanation:

$A^{2}$ + $B^{2}$ = $C^{2}$

7 $6^{2}$ + 5 $7^{2}$ = $C^{2}$

3249+5776 = 9025

$\sqrt[]{9025}$ = 95

kvasek [131]3 years ago

4 0

Answer:

137 i think

Step-by-step explanation:

You might be interested in

Find the 64th term of the following arithmetic sequence.<br> 8,11,14,17

ruslelena [56]

Answer: 197

Step-by-step explanation:

The nth term is 3n+5

so the 64th term will be

(3 x 64)+5

192+5

= 197

7 0

4 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$