The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
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Answer:
Step-by-step explanation:
There are two. This can be factored which will find both of them.
y = (x - 3)(x - 1)
x - 3 = 0
x - 3 + 3 = 3
x - 1 = 0
x - 1 + 1 = 1
x = 1
The zeros are (3,0) and (1,0)
Answer:
(6x+3) (4x-5) = 24x^2 -30x +12x -15 = 24x^2 -18x -15
I get the same answer. I guess we're both wrong?
Or do they want it reduced to:
8x^2 -6x -5
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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