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miskamm [114]
3 years ago
12

What is the value of "w" ?

Mathematics
1 answer:
NISA [10]3 years ago
3 0

Answer:

w = \sqrt{147}

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

w² + 7² = 14²

w² + 49 = 196 ( subtract 49 from both sides )

w² = 147 ( take the square root of both sides )

w = \sqrt{147}

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Can someone please help me with the answer.
Elza [17]

Answer:

The answer to your question is : f(-2) = 2

Step-by-step explanation:

Just look for -2 in the x- axis and look for some line or point, vertical to number two.

In your example you can find a point two units upward the x-axis.

5 0
3 years ago
An entrepreneur estimates that the total profit (profit = total revenue minus total cost) from his proposed company will be give
EastWind [94]
P ( x ) = x³ - 4 x² + 3 x - 12 = 
= x² ( x - 4 ) +3 ( x - 4 ) = ( x - 4 ) · ( x² + 3 ) 
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Answer: In 4 years the company will break even.
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3 years ago
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HACTEHA [7]

Answer:

c is correct

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the value of log 43? Use the calculator. Round your answer to the nearest tenth.
Bad White [126]

Answer:

The value of log  43is 1.633

Step-by-step explanation:

Explanation:

Suppose you know that:

\begin{array}{l}{\log 2 \approx 0.30103} \\{\log 3 \approx 0.47712}\end{array}

Then note that:

43=\frac{129}{3} \approx \frac{128}{3}=\frac{2^{7}}{3}

So

\log 43 \approx \log \left(\frac{2^{7}}{3}\right)=7 \log 2-\log 3 \approx 7 \cdot 0.30103-0.47712=1.63009

We know that the error is approximately:

\log \left(\frac{129}{128}\right)=\log 1.0078125=\frac{\ln 1.0078125}{\ln 10} \approx 0.00782 .3=0.0034

So we can confidently give the approximation:

\log 43 \approx 1.633

6 0
3 years ago
An experimenter is studying the effects of temperature, pressure, and different type of catalysts.
Gwar [14]

Answer: 60

Step-by-step explanation:

Given : The number of choices for different temperatures = 3

The number of choices for different pressures = 4

The number of choices for different catalyst = 5

Since , the experimenter is studying the effects of temperature, pressure, and different type of catalysts.

Then by using the Fundamental principle of counting , we have

The number of  experimental runs are available = (number of choices for  temperatures ) x (number of choices for pressures) x( number of choices for  catalyst)

= 3 x 4 x 5 = 60

Hence, the number of experimental runs are available = 60

6 0
3 years ago
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