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shusha [124]

2 years ago

latex-formula">

Mathematics

2 answers:

Monica [59]2 years ago

3 0

If you’re trying to find y the answer should be anything that equals more than negative 7 for example y could be 10

Marrrta [24]2 years ago

3 0

Y more than or equal -2

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What are the restrictions of the domain of the function F(x) = 1/x^2-9

Sonbull [250]

$f(x)=\frac{1}{x^2-9}$

The denominator can't be equal to 0.
$x^2-9 \not= 0 \\
x^2 \not= 9 \\
x \not= -3 \ \land \ x \not= 3$

The domain is all numbers except -3 and 3.
$x \in \mathbb{R} - \{-3, 3 \}$

6 0

3 years ago

A warehouse worker fills 150 orders per day on average. From day to day, the number of orders varies by 2%. What is the range of

choli [55]

Answer:

The range is from 147 to 153 orders per day

Step-by-step explanation:

orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.

That is, by 2%.

First, we need to find the decimal of 2%, so

2/100 = 0.02

We multiply this with the average number of order, 150, to get the varying amount:

0.02 * 150 = 3

Thus, the range would be:

150 - 3 = 147

150 + 3 = 153

The range is from 147 to 153 orders per day

5 0

3 years ago

4-2(x+7)=3(x+5) using the equation solver

Viefleur [7K]

Answer:

x = -5

Step-by-step explanation:

We don't know what equation solver you're supposed to use. Here are the results from one available on the web.

8 0

3 years ago

Read 2 more answers

Five times the sum of 3 and twice some numbers is 70. What is the number?

Anna11 [10]

Let x represent some number
Sum of 3 and twice some number = 3 +2x
Five times the sum of 3 and twice some number: 5(3+2x)

5(3+2x)=70
15+10x=70
Subtract 15 from both sides to have 10x by itself
10x=55
Divide 10 on both sides to get x by itself
x=55/10
x=5.5

Hope this helped

8 0

3 years ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$