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3 years ago

11

There are 10 doors to a coliseum. In how many ways can a person go in and out if one can enter any door but leave using another

door? Use permutation formula (P(n,r)) to solve.

1 answer:

love history [14]3 years ago

5 0

Answer:

90 is the answer

Step-by-step explanation:

P(10,2) = $\frac{10!}{(10-2)!}$ = $\frac{10!}{8!}$ = $\frac{10x9x8!}{8!}$

10x9

=90

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