Answer:
The answer is D. 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.
(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic =
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer:
Step-by-step explanation:
Use the square of a binomial theorem
=
Now expand the given equation:
Hope this helps :)
Have a great day!
Answer:
46,125
Step-by-step explanation:
2.5% = .025
45,000 * .025 = 1,125
45,000 + 1,125 = 46,125
1,099= 1,100
HOPE THIS HELPS!!!