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3 years ago

14

A jar contains five red marbles and three green marbles. A marble is drawn at random and not

1 answer:

Alex787 [66]3 years ago

5 0

5+3=8
Every time you draw, its minus one from denominator

1st marble red: 5/8

2nd marble green: 3/7

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Mr. Harrison spent about $3600 on plane tickets for a family vacation. If each plane ticket cost $585, what is the largest numbe

Zepler [3.9K]

Answer:

6 tickets

Step-by-step explanation:

Amount spent by Mr Harrison on plane tickets = $3600

Cost of each ticket = $585

Thus, largest number of tickets purchased is;

n = 3600/585

n = 6.15

Approximating to the nearest whole number gives 6 tickets

3 0

2 years ago

Solve<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba-1%7D%7Ba-3%7D%20%3D%5Cfrac%7Ba%2B1%7D%7Ba-4%7D" id="TexFormula1" title="

bixtya [17]

Answer:

$a=\frac{7}{3}$

Step-by-step explanation:

$\frac{a-1}{a-3}=\frac{a+1}{a-4}$

$(a-1)(a-4)=(a-3)(a+1)$

$a^2-5a+4=a^2-2a-3$

$-5a+4=-2a-3$

$-3a+4=-3$

$-3a=-7$

$a=\frac{7}{3}$

3 0

2 years ago

Bryan cuts a piece of cardboard in the shape of a trapezoid. The area is 43.5 square centimeters. If the bases are 6 centimeters

Juli2301 [7.4K]

The answer will be 369.75 Hopes this helps. :)

3 0

3 years ago

Please help it’s just only two questions

taurus [48]

Answer:

Question-6;

The value of $x=7.5$ $in$

Question-7;

So the Answer is 'A'

Step-by-step explanation:

Question-6;

From the portion 'ABCD';

Given the area of rectangle 'ABCD' is $30$ $in^{2}$ , $AD=4$ $in$ and $AD=x$ $in$

We have the formula to find the area of rectangle;

Area of rectangle 'ABCD' $=AD\times DC$

$30=4\times x$

$x=\frac{30}{4}$

$x=7.5$ $in$

So the value of $x=7.5$ $in$ .

Question-7;

From figure;

Given;

All values $AB=CD=FG=IJ=9$ $cm$ , $AC=BD=5$ $cm$ , $CF=DG=4$ $cm$ , $FI=GJ=3$ $cm$ and $EF=GH=3$ $cm$

In Rectangle 'ABIJ' have three sub-rectangle which are 'ABCD' , 'CDFG' and 'FGIJ'

Area of Rectangle 'ABIJ' equal to sum of area of Rectangle 'ABCD' , area of Rectangle 'CDFG' and area of Rectangle 'FGIJ'

Area of Rectangle 'ABIJ' $=(AB\times AC)+(CD\times CF)+(FG\times FI)$

Plug all values in above equation,

Area of Rectangle 'ABIJ' $=(9\times 5)+(9\times 4)+(9\times 3)$

Area of Rectangle 'ABIJ' $=108$ $cm^{2}$

Also from figure;

$\bigtriangleup CEF$ and $\bigtriangleup DGH$ have same Area.

Total Area of this two triangle $=2\times Area of \bigtriangleup CEF$

Total Area of this two triangle $=2\times\frac{1}{2}\times BASE \times HIGHT$

Total Area of this two triangle $=2\times\frac{1}{2}\times EF \times CF$

Plug 'EF' and 'CF' values in above equation,

Total Area of this two triangle $=2\times \frac{1}{2} \times3 \times 4$

Total Area of this two triangle $=12$ $cm^{2}$

∴ Total surface area of the building block is $(108+12)=120$ $cm^{2}$

7 0

3 years ago

If you can type 50 words per minute, how many minutes would it take you to type a 500 word essay

Lyrx [107]

Answer:

10 minutes.

Step-by-step explanation:

500÷50=10.

<em><u>Could I please have BRAINLIEST?</u></em>

5 0

4 years ago

Read 2 more answers