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Alex_Xolod [135]
3 years ago
12

width of a rectangle is five lesson three times the length of the rectangle if the perimeter of the rectangle is 70 inches what

are the dimensions of the rectangle ?
Mathematics
1 answer:
gregori [183]3 years ago
8 0

Answer:

Length = 10 inches

width = 25 inches

Step-by-step explanation:

Let the length of the rectangle be X inches

width = (3x - 5) inches

 Perimeter of rectangle =  70 inches

     2 * ( l + b)   = 70

2 * ( x + 3x - 5) = 70

             4x - 5 = 70 / 2

             4x - 5 = 35

                    4x = 35 + 5

                    4x = 40

                       x = 40/4

                        x = 10

Length = 10 inches

width = 3x - 5 = 3*10 - 5 = 30- 5 =  25 inches

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zzz [600]

The question is missing figure and the options. So, the figure is attached alongwith the options

Answer:

Correct options: (1), (2) , (7) and (8)

Step-by-step explanation:

Given:

Lines a and b are parallel.

Consider a║b  and 'd' be a transversal  then,

Statements                                    Reasons

1. ∠BXZ = ∠AZP = 58°                Corresponding angles are equal

∴ m∠2 = 58°

2. ∠BYC = ∠XYZ = (4x-10)° Vertically opposite angles are equal

Now, consider a║b and 'c' be a transversal then,

Statements                             Reasons

1. ∠XYZ = ∠QZU = (4x-10)°  Corresponding angles are equal

∴ m∠1 =  (4x-10)°

2.∠PZA + ∠PZQ + ∠QZU = 180° Sum of angles on a straight line is 180°.

3. 58\° +(3x-1)\°+(4x-10)\° = 180\°      Substitution property

4. 47\° + 7x= 180\°                   Combining like terms

5. 7x=180\°-47\°                         Subtraction property of equality

   ∴ 7x = 133\°

6. x = 19\°                                 Division property of equality

Plug in x = 19\ in\ (3x-1)\°\ and\ (4x-10)\°, we get

(3x-1)\° = (3(19)-1)\° = 56°

(4x-10)\° = (4(19)-10)\° = 66°

So, (3x-1)\° \ne (4x-10)\°

Hence, options (1), (2) , (7) and (8) are correct.

4 0
3 years ago
Read 2 more answers
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IgorLugansk [536]

The diagram of the triangle is missing, so i have attached it.

Answer:

Surface area = 9.425 sq.units

Step-by-step explanation:

When a triangle having an interior angle as 30°, 60° or 90° is rotated, then a cone is formed.

Thus, we need to find the surface area of the cone.

Surface area of a cone is πr ² + πrL

where;

r = radius of the cone

L = slant height of the cone

I have attached the cone formed as the second image.

Looking at the image of the cone, we need to find the radius and slant height.

From the triangle image, we can use trigonometric ratios;

tan 30 = BC/AB

In surd form, BC/AB = 1/√3

Thus, BC is equivalent to 1 and AB equivalent to √3

Using Pythagoras theorem, we can find AC.

(AC)² = (AB)² + (BC)²

AC = √[(AB)² + (BC)²]

AC =√[(√3)² + (1)²]

AC = √[3 + 1]

AC = √4

AC = 2

So, radius, r corresponds to BC = 1

And slant height L corresponds to AC = 2.

Thus,r = 1 and L = 2

So,

Surface area of cone = π(1)² + π(1)(2) = π + 2π = 9.425 sq.units

5 0
4 years ago
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mihalych1998 [28]
<span>A(x, y) → (x - 3, y + 1)</span>
8 0
3 years ago
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gizmo_the_mogwai [7]

Answer:

145°

Step-by-step explanation:

x°+70°=(2x-5)°

x°+70°=2x°-5°

70°+5°=2x°-x°

75°=x°

x=75

JKM=(2x-5)°

=(2x75-5)°

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3 years ago
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GarryVolchara [31]

Answer:

11.2

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points (x_1, y_1) and (x_2,y_2) is equal to \sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is \sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}

3 0
3 years ago
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