Answer:
0.8 of a cake
Step-by-step explanation:
all you do is divide 4 by 5
Answer: <em>x=4</em>
Step-by-step explanation:
<em>1+3x=x+9</em>
<em> -x -x</em>
<em>1+2x=9</em>
<em>-1 -1</em>
<em>2x=8</em>
<em>Divide by 2 on each side</em>
<em>Final result</em>
<em>x=4</em>
Answer:
This question requires a comparison between two different variables 6% and 16% values. If we let x=$ loaned on 6% loans and y=$ loaned on 16% loans, then we can relate two equations.
0.06x + 0.16y = $1500 --> referencing the interest earned from each percentage loaned.
x + y = $16000 --> referencing the total amount of money loaned out.
Rearrange either equation and substitute for a value in the other equation or use elimination to determine each individual variable.
Step-by-step explanation:
Answer: 5.44449
step-by-step explanation:
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
