Answer:
Step-by-step explanation:
Recall that ![\frac{x}{9}=\lfloor \frac{x}{9} \rfloor + 0.\overline{[x\:\mod9]}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B9%7D%3D%5Clfloor%20%5Cfrac%7Bx%7D%7B9%7D%20%5Crfloor%20%2B%200.%5Coverline%7B%5Bx%5C%3A%5Cmod9%5D%7D)
.
Therefore, 
.
Answer:
3.95 km
Step-by-step explanation:
The computation is shown below:
As both left for school
Tom walked to school on route A i.e. 4.50 kilometer
And, Jane walked to school on route B i..e 8 kilometers & 450 meters i.e. 8.45 kilometers
So, the more km that jane would take to reach to school as compared with Tom is
= 8.45 km - 4.50 km
= 3.95 km
If line 3x + 4y = 24 cuts the x axis at point A, then point A is ur x intercept of line 3x + 4y = 24. To find the x int, sub in 0 for y and solve for x.
3x + 4y = 24
3x + 4(0) = 24
3x = 24
x = 24/3
x = 8....so point A is (8,0) <===
if line 3x + 4y = 24 cuts the y axis at point B, the point B is the y int. of 3x + 4y = 24. To find the y int, sub in 0 for x and solve for y
3x + 4y = 24
3(0) + 4y = 24
4y = 24
y = 24/4
y = 6......so point B is (0,6) <===
if point C is equidistant from point A and point B, then it is the midpoint.
midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(8,0)....x1 = 8 and y1 = 0
(0,6)...x2 = 0 and y2 = 6
time to sub and solve
m = (8 + 0)/2 , (0 + 6)/2
m = (8/2),(6/2)
m = (4,3) <=== this is point C
