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miv72 [106K]
3 years ago
5

Marcus jumped “x” feet.

Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer:

Do u know the answer

Step-by-step explanation: I am doing a test pls help

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Find three ratios equivalent to the ratio described in each situation.
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Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

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3 years ago
1 2/3-2 1/3 what’s the answer
scoray [572]

Answer:

-\frac{2}{3}

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4 years ago
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If the quadratic formula is used to solve 2x2 = 8x -3, what are the solutions
seraphim [82]

Answer:

2x2 = 8x-3

4 = 8x - 3 | +3

7=8x

x=7/8

Step-by-step explanation:

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4 years ago
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Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. The area
Andreyy89

The dimensions of the original photo is: X = 11

<h3>Meaning of dimension.</h3>

A dimension can be defined as the parameters, measurement, scale  or size of an object or figure.

A dimension is so important as is gives us a visual representation of an object.

<h3>Analysis</h3>

(x-3)^{2} = 64

(x-3) = \sqrt{64}

x = 8 + 3

x = 11

In conclusion, The dimensions of the original photo is: X = 11

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6 0
2 years ago
Question 1 options:Residents in Portland, Oregon think that their city has more rainfall than Seattle, Washington. To test this
dimaraw [331]

Answer:

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0

P-value = 0.1290

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

Step-by-step explanation:

We have to test the hypothesis of the difference between means.

The claim is that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0

The significance level is 0.10.

The sample for Portland, of size n1=45, has a mean of M1=37.50 and standard deviation of s1=1.82.

The sample for Seattle, of size n1=35, has a mean of M1=37.07 and standard deviation of s1=1.68.

The difference between means is:

M_d= M_1-M_2=37.50-37.07=0.43

The standard error for the difference between means is:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1.82^2}{45}+\dfrac{1.68^2}{35}}=\sqrt{ 0.0736+0.0688 }=\sqrt{0.1424}\\\\\\s_{M_d}=0.3774

We can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.43-0}{0.3774}=1.1393

The degrees of freedom are:

df=n1+n2-2=45+35-2=78

Then, the p-value for this one-tailed test with 78 degrees of freedom is:

P-value=P(t>1.1393)=0.1290

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

7 0
3 years ago
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