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Basile [38]
3 years ago
9

Q = 3x + 9x? idk this one lol

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

<em>q</em> = 12<em>x</em>

Step-by-step explanation:

<em>q</em> = 3<em>x</em> + 9<em>x</em>

Combine like terms

<em>q</em> = 12<em>x</em>

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PLEASE HELP!!!! I NEED TO GET THIS DONE!!!
exis [7]

Step-by-step explanation:

\frac{6}{4}  = 1.5

m<G = 180-90-37= 53°

measure of DG = 5*1.5= 7.5

4 0
3 years ago
How do I solve this ?
Alja [10]

Answer:

g(-9) = 1

Step-by-step explanation:

g(-9) is the value of the function at x = -9

Go over the x = -9 and go up until you hit the blue line

Read the value of y

g(-9) = 1

5 0
3 years ago
Read 2 more answers
3. James travels 3,247 m to the park, then 582 m to the store. He then travels 1,634 m back to his house.
umka21 [38]
C approximately 5460 meters
4 0
3 years ago
Read 2 more answers
Need Help! 10 points!
Dominik [7]
The answer is d because 4+8=12 and they are 4 units away from eachother:)
6 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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