Question

Find the zeroes of the quadratic polynomial 4x²-4x+1 and verify the relation between its zeroes and coefficients

Answer 1

Answer:

A) zeros are x = ½ or x = ½

B) >> sum of zeros = (-Coefficient of x)/(Coefficient of x²)

>> Product of the zeros = Constant term/Coefficient of x²

Step-by-step explanation:

To find the zeros, we will equate the polynomial to zero.

Thus;

4x² - 4x + 1 = 0

Using quadratic equation, we can find the zeros.

x = [-(-4) ± √((-4)² - (4 × 4 × 1))]/(2 × 4)

x = (4 ± 0)/8

x = 4/8 and x = 4/8

Thus, zeros are x = ½ or x = ½

Now, to find the relationships between its zeroes and coefficients;

Sum of zeroes = ½ + ½ = 1

This is equal to -b/a = -(-4)/4 = 1.

Thus;

sum of zeros = (-Coefficient of x)/(Coefficient of x²)

Product of zeros = ½ × ½ = ¼

c/a = 1/4

This is equal to the product of the zeros.

Thus;

Product of the zeros = Constant term/Coefficient of x²