For the training adaptation of maximum strength, 1 to 5 repetitions per set is recommended.
The one-repetition maximum test, also called a one-rep max or 1RM, is used to find out the heaviest weight you can lift just once.
If Maximal strength is desired, it is best achieved by performing repetitions at 85 to 100 % of the one-repetition maximum (1RM).
Formula to find the repetition is
weight used x (reps done x 0.33 + 1) = 1RM
so,
Reps done = {{1RM/weight used} - 1}/ 0.33
By this find the no of reps are recommended for maximum strength.
The maximum strength is achieved by doing the number of reps by 85 to 100% of the value of 1 RM.
So,
For the training adaptation of maximum strength, 1 to 5 repetitions per set is recommended.
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Answer:
-1/23x+-1.043478261
Step-by-step explanation:
Distribute -1/23 to x and 24
-1/23 times x equals -1/23x
-1/23 times 24 equals -1.043478261
So -1/23(x+24) = -1/23x+-1.043478261
Answer:
Son's Age: 11
Mary's Age: 33
Step-by-step explanation:
Let set Mary and her son as variables,
M = Mary's age
S = Mary's son age
<u>Breakdown:</u>
"Mary is three times as old as her son"
M = 3S
"In <em>12 years</em>, Mary's age will be one less than <u>twice her son's</u> age"
M <em>+ 12</em> = <u>2</u>(S <em>+ 12</em>) - 1
we add 12 to both sides as it will be in 12 years for both
We know that M = 3S, so we plug this in
3S + 12 = 2(S + 12) - 1
Now solve for <em>S (son's age),</em>
3S + 12 - 12 = 2(S + 12) - 1 - 12
3S = 2(S + 12) - 13
3S = 2S + 24 - 13
3S - 2S = 2S - 2S + 24 - 13
S = 24 - 13
S = 11
To find <u>Mary age</u>, plug in her son age ,
M = 3S
M = 3(11)
M = 33
Learn more about Substitution here: brainly.com/question/22340165
1. write it as it is
2. 70.04 since to round you go two decimal places and because the place after that is higher than 5 you round 3 up to 4.
3. DNE since you can’t divide any number by 0
