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maks197457 [2]
2 years ago
12

Which number has two lines of symmetry? 101 619 33 18 not multiple answer

Mathematics
1 answer:
podryga [215]2 years ago
8 0

Answer:

The number is 33

Step-by-step explanation:

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tatuchka [14]
*triple phytagoras*
first triangle h = second triangle h = 24 in

x = 7 (triple phytagoras)
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2 years ago
So desperate. Last question on my HW and I can't do it.
vladimir2022 [97]

Will you please either write the question or upload a picture of it so we can help you with it?

7 0
3 years ago
Question is attached!​
saul85 [17]

Answer:

$3,000 was invested in the account that gained 13%

$17,500 was invested in the account that lost 10%

Step-by-step explanation:

Let the amount in both accounts be x and y

x for the first and y for the second

Adding both is 20,500

x + y = 20,500 •••••(i)

First account earned 13% profit

= 13/100 * x = 0.13x

Second account, a loss of 10%

= -10/100 * y = -0.1y

Total loss of -1,360

This is;

-0.1y + 0.13x = -1,360 •••••••(ii)

From i, x = 20,500-y

Insert this into ii

-0.1y + 0.13(20,500-y) = -1,360

-0.1y + 2665 -0.13y = -1360

-0.23y = -1360-2665

-0.23y = -4025

y = -4025/-0.23

y = 17,500

To get x, we have

x = 20,500 -y

x = 20,500- 17,500

x = 3,000

3 0
2 years ago
If you can read this please answer it
Harlamova29_29 [7]
Indirect proportion:   y = k/x.

Here, y = 2 / (3x); x is in the denominator of the fraction.  Thus, this equation does represent indirect proportion, with k = (2/3).

       2/3
y = -------
         x
6 0
3 years ago
A train slows down as it rounds a sharp horizontal turn, going from 92.0 km/h to 54.0 km/h in the 16.0 s that it takes to round
Mnenie [13.5K]

Calculation of centripetal acceleration(ac):

a_c=\frac{v^2}{r}

we can change our speed in terms of m/s

v=54km/h=54*\frac{1000}{3600} m/s

now, we can plug these values

a_c=\frac{(54*\frac{1000}{3600})^2}{130}

a_c=1.73077m/s^2

Calculation of tangential acceleration(at):

a_t=\frac{\Delta v}{\Delta t}

now, we can plug values

a_t=\frac{(54-92)*\frac{1000}{3600} }{16}

now, we can simplify it

a_t=-0.65972 m/s^2

Calculation of resultant acceleration:

a=\sqrt{(a_c)^2+(a_t)^2}

now, we can plug values

a=\sqrt{(1.73077)^2+(-0.65972)^2}

a=1.85224m/s^2.............Answer

4 0
3 years ago
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