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laiz [17]
3 years ago
6

A university lecture hall has 100 seats. During class, 30% of the seats are empty. How many students are attending class?

Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

70 students

Step-by-step explanation:

100=100% so -30 to get 70 students

Shtirlitz [24]3 years ago
3 0

Answer:

70 students are attending class

Step-by-step explanation:

100% - 30% = 70%

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If a, b, and c are prime numbers, do (a +<br> b.and c have a common factor that is greater than 1 ?
valina [46]

Let's do the math. In the example a =2, b = 3, c = 5. If we are trying to see if the sum of these numbers has a common factor more than 1 do the math. 2 + 3 + 5 = 10. Ten has four factors which are 1, 2, 5, and 10. So the answer to your question is yes.

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olasank [31]

Answer:

use photomath

Step-by-step explanation:

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3 years ago
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Prove algebraically that the straight line with equation x=2y+5 is a tangent to the circle with equation x^2+y^2=5
zmey [24]

Differentiate both sides of the equation of the circle with respect to x, treating y=y(x) as a function of x:

x^2+y^2=5\implies2x+2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac xy

This gives the slope of any line tangent to the circle at the point (x,y).

Rewriting the given line in slope-intercept form tells us its slope is

x=2y+5\implies y=\dfrac12x-\dfrac52\implies\mathrm{slope}=\dfrac12

In order for this line to be tangent to the circle, it must intersect the circle at the point (x,y) such that

-\dfrac xy=\dfrac12\implies y=-2x

In the equation of the circle, we have

x^2+(-2x)^2=5x^2=5\implies x=\pm1\implies y=\mp2

If x=-1, then -1=2y+5\implies y=-3\neq2, so we omit this case.

If x=1, then 1=2y+5\implies y=-2, as expected. Therefore x=2y+5 is a tangent line to the circle x^2+y^2=5 at the point (1, -2).

7 0
3 years ago
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Please answer these thank u​
balu736 [363]

1. 3*3 + 3*8 = 9+24=33

2. 4*4+.5*2*4+5*5= 16+4+25=45

3. 5*10+4*10= 90

4. 24+.5*4*4 = 32

3 0
2 years ago
Find the coordinates of the midpoint of the segment whose endpoints are h(6,4) and k(2,8)
ozzi

Answer:

(4,6)

Step-by-step explanation:

we know that

The formula to calculate the coordinates of the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have that

The coordinates of hk

h(6,4), k(2,8)

substitute in the formula to calculate the midpoint

M(\frac{6+2}{2},\frac{4+8}{2})

M(\frac{8}{2},\frac{12}{2})

M(4,6)

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3 years ago
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