Let the origin of the coordinate system be the position of ship B at noon. Then the distance between the ships as a function of t (in hours) is
.. d = √((30 +23t)² +(17t)²)
.. = √(818t² +1380t +900)
The rate of change of distance with respect to time is
.. d' = (1/2)(2*818*t +1380)/√(818t² +1380t +900)
.. = (818t +690)/√(818t² +1380t +900)
At t=4, this is
.. d' = (818*4 +690)/√(818*16 +1380*4 +900)
.. = 3962/√19508
.. ≈ 28.37 . . . . . knots
The distance between the ships is increasing at about 28.37 knots at 4 pm.
Answer:
the pattern step number of second step is added to number of balls used of first step to get number of balls used of second step
that is
1 + 2 ( number of balls added to pattern step number) = 3 (number of balls used)
in the same way
6 + 4 = 10 ( first blank )
5 + 10= 15 ( second blank)
15 + 7 = 22 ( third blank )
22 + 8 = 30 ( fourth blank)
1)35 degrees
2)50 degrees
3)91 degrees
4)118 degrees
Answer:
C = 5/2 - 6/7
Step-by-step explanation:
Answer:
300
Step-by-step explanation:
2000-500= 1500
1500/5= 300