Answer : p(only z)=0.40 and p(only u)=0.08
Explanation :
We have given that ,
p(u)=0.22,
p(z∪u)=0.62,
p(z)=0.54
By using probability rule of union of 2 events, we have,
p(z)+p(u)-p(z∩u)=p(z∪u)
⇒0.54+0.22-p(z∩u)=0.62
⇒0.76-p(z∩u)=0.62
⇒(-)p(z∩u)=0.62-0.76
⇒(-)p(z∩u)= (-)0.14
⇒p(z∩u)=0.14
Now,
p(only z)=p(z)-p(z∩u)
=0.54-0.14
=0.40
and,
p(only u)=p(u)-p(z∩u)
=0.22-0.14
=0.08
∴ Each probability will be
p(only z)=0.40
p(only u)=0.08
This is the quadratic equation
x = -b +/- (sq root)(b^2 - 4(a)(c) all over 2a
If inside the square root the value is <0. You can't get an answer.
Now figure the rest out
Answer:
.53
Step-by-step explanation:
Answer:
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