Trapezoid ABCD is shown. A is at negative 5, 1. B is at negative 4, 3. C is at negative 2, 3. D is at negative 1, 1. A) x-axis, y=x, y-axis, x-axis b) x-axis, y-axis, x-axis c) y=x, x-axis, x-axis d) y-axis, x-axis, y-axis, x-axis The best answer is C180 rotation wud take that point to 4th quadrant reflection in x-axis takes that to 1st quadrant <span>reflection in y-axis brings it back to 2nd quadrant again. So, the sequence of transformations will bring A back to where it started </span> Hope this Helps! :)
