Step-by-step explanation:
secants originating from the same point have the same relative length relationship :
outside part × sum of outside and inside parts
is the same for every secant from the same point.
so,
5×(7+5) = 6×(2x-8+6) = 12x - 12
60 = 12x - 12
12x = 72
x = 6
WV = 2x - 8 = 2×6 - 8 = 12 - 8 = 4
so, B is correct.
Answer:
253.48
Step-by-step explanation:
Hello this is answer
Answer:
24
Step-by-step explanation:
what is the smallest number which is a multiple of both 8 and 12? so, an multiple of 8 must have 2 as a factor at least 3 times. Similarly, multiples of 12 have at least two 2's and one 3. so we need 2x2x2x3 or 24 if every factor is to be included.
I'm not the best at explaining but you can search google to get the better Idea.
(btw this is for the fist question)
Answer:
Step-by-step explanation:
To solve this we should use the Euclidean division :
- Our polynomial function is 16-2x³-6x²+x+9=-2x³-6x²+x+9
- we should divided by : 4+3x-2=3x+2 and see the rest
Here is a picture with the operation
- the rest is 47/9 so the number I SHOULD SUBSTACT IS 47/9
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
